How much kinetic energy to kill a deer.

Those numbers to me are a farce. Broadheads kill with less than 100lbs of energy. Probably half of that. They are unwritten rules; what you do with them is entirely up to you. To answer your 1499 FT-LBS question, yes, it will. I harvested a bull elk at 931Y with a tad over 1400 FT-LBS.

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New Hampshire. "Experts" will tell you anywheres from 1000-1200 ft/lbs. This, to me, is waaaaay overkill. One gentlemen, whos advice I trust completely, has a good formula. 3 times as many ft/lbs is needed than the games weight. Meaning if you want to shoot 200 lb deer then 600 ft/lbs should do the job very nicely.The forces and kinetic energy required to penetrate the isolated heads of calves, adult beef cattle, sheep and red deer with a metal probe the same diameter as the bore of an experimental pistol were determined. Approximately 16 and 127 Joules were required to penetrate the heads of adult sheep and cattle, respectively.Smaller calibers require great skill. When you increase the caliber size from .177 to .22, .25, .30, .357, .45 and upward, then the precision required for a humane kill decreases. There are some calibers that are very well suited for various types of game. The general rule in the airgun world has always been .177 for feathers and .22 for fur.If the potential accelerating the electrons is 10,000 volts (we say 10 kilovolts (KV) ), how much kinetic energy in joules does one electron have as it leaves the "gun" on its way to the screen? How fast is that electron going, as a fraction of the speed of light? How long would it take to go 25 cm from the gun to the screen?

Kinetic energy is physics ke=.5 x mass x velocity squared. For shooting we have to add in the acceleration due to gravity to convert from weight to mass and convert from grains to pounds so the formula becomes Ke= grains x velocity squared/ 2 x 7000 x 34.17 The 34.17 is relative to lat/long and elevation but that number is the accepted one …#1 · Jan 29, 2011. I just wanna know peoples opinions on recommended kinetic energy for elk. Ive got some shoulder damage and cant pull 70lb bows anymore. Any ideas? Like. …

All but the .243 are still carrying the generally accepted 1,000 ft.-lbs. of energy necessary to kill a deer out to 500 yards, which I grant you is farther than we have any business shooting at deer-size gam. At the far more practical distance of 300 yards, which is still a long shot, every cartridge on that list will kill a deer, antelope or ...

As I understand it, it assumes pretty much perfect headshot placement. 1) Gray squirrel/Fox Squirrel - 4.5fpe. 2) Eastern Cottontail/Swamp Rabbit - 4fpe. 3) Jack Rabbit White, Black, and Jack O' lope - 4.5fpe. 4) Raccoon/ Bandit - 9fpe.. if it's a big one, 10fpe. 5) Virginia Opossum/ County Rat - 10fpe.One other thing about comparing rifle cartridges to pistol cartridges, as far as ranges go, rifles usually carry way too much energy for their own good-what I mean by this is a .30-06 or a .300win mag can easily kill a deer at 1000yrds, but there are about 6 guys (non-military) in the world that could make that shot under hunting conditions ...velocity x velocity x total arrow weight (in grains) divided by 450,240. How much do your arrows weigh in grains. How fast (in feet per second) are your arrows. to calculate your KE (kinetic Energy) Your KE = How much KE …Therefore, the heavier the missile, the more kinetic energy there is. Overall, it takes around 21 to 45 Joules of kinetic energy at the point of impact to pass through any large-sized animal. Body movement after a shot. There are certain telltale signs that show the hunter where the animal was hit based on the movement of the animal right after ...Those elements are what is needed to calculate kinetic energy. For example, my bow fires a 400 grain arrow (broadhead included) at 305 feet per second. To find the kinetic energy, I multiply 305 by 305, then multiply by 400. I get 37,210,000. Divide that by 450,240 and the kinetic energy is 82.64 ft. lbs. I suggest using a calculator.

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Nov 30, 2021 · Those elements are what is needed to calculate kinetic energy. For example, my bow fires a 400 grain arrow (broadhead included) at 305 feet per second. To find the kinetic energy, I multiply 305 by 305, then multiply by 400. I get 37,210,000. Divide that by 450,240 and the kinetic energy is 82.64 ft. lbs. I suggest using a calculator.

Question: (13%) Problem 6: During an ice show, a 52.5-kg skater leaps into the air and is caught by an initially stationary 87.5 kg skater 5 % Part(a) What is their final speed, în meters per second, assuming negligible friction and that the 52.5 kg skater's initial horizontal speed is 4.25 m/s? v 1.59 Correct! 50% Part (b) How much kinetic energy is lost, in joules?Here are the crossbows that I think are the best crossbow for deer hunting at the moment. 1. Ravin R20 Crossbow Package. Check Latest Price. Specifications | Speed: 430 FPS; Kinetic Energy: 164 ft.lbs; Power Stroke: 13 Inches; Draw Weight: 220 LBS; Axle To Axle: 6 / 10.5 Inches; Length: 34.5 Inches; Weight: 7.1 LBS.Imagine that much kinetic energy concentrated into an object the size of a bullet, or a pellet, or a super cool .50 caliber arrow. Now imagine 350 foot pounds in a bullet, or a pellet, or a super cool .50 caliber arrow, and then remember that many PCP’s intended to hunt deer and other types of bigger game will exceed that number.The impact forces in an auto collision are much smaller than the needle, but that car collision may well kill. Momentum and energy are much important concepts than force. Which of momentum or energy is more important depends on the circumstances. ... (determining the kinetic energy of the object at impact e.g. a 10kg mass falling from 1m has 10 ...A 12-kg sled is moving at a speed of 3.0 m/s. At which of the following speeds will the sled have twice as much kinetic energy? 4.2. Why is the gravitational potential energy of an object 1 meter above the moon's surface less than its potential energy 1 meter above Earth's surface? The moon's acceleration due to gravity is less.Here are a couple home remedies you might want to try to keep deer away from your lawn or garden. Expert Advice On Improving Your Home Videos Latest View All Guides Latest View All...

Vehicles moving on the road network carry a high amount of kinetic energy. The kinetic energy of each vehicle (Halliday et al., 2003) is related to the mass and the speed of the vehicle in the form: (2) K = 1 2 × m × v 2 where K: kinetic energy of the object; m: mass of the object; v: velocity of the object. Some of the kinetic energy ...In order to kill a deer with a single FPE, it would need to be a very large deer. The average whitetail deer weighs between 120 and 200 pounds, so it would take at least 1,200 ft-lbs of energy to kill one. That’s equivalent to about 12 FPE. So, while it is possible to kill a deer with a single FPE projectile, it’s not likely.An explosion causes an object, initially at rest, to break into two pieces. One of these pieces has twice as much kinetic energy as the other. What is the ratio of their masses? Which one has the larger mass? Is it the one with the larger kinetic energy, or the one with the smaller kinetic energy? All I want to know is what kinds of Physics ...10 The diagram shows the path of a stone that is thrown from X and reaches its maximum height at Y. path of stone X6 The stone gains 10J of gravitational potential energy as it moves from X lo Y. The stone has 2.0J of kinetic energy at Y. Air resistance can be ignored. How much kinetic energy did the stone have immediately after it was thrown at X?Naturally, the kinetic energy of an object at rest should be zero. Thus an object's kinetic energy is defined mathematically by the following equation…. K = ½mv 2. Thomas Young (1773-1829) derived a similar formula in 1807, although he neglected to add the ½ to the front and he didn't use the words mass and weight with the same precision we do nowadays.Assume the deer remains on the car. 27. ... How much kinetic energy is transferred to the rifle-shoulder combination? The pain is related to the amount of kinetic energy, which is significantly less in this latter situation. (e) Calculate the momentum of a 110-kg football player running at 8.00 m/s. Compare the player's momentum with the ...

Kinetic windstream technology is an innovative form of renewable energy that harnesses the power of wind to generate electricity. It works by capturing the kinetic energy in wind a...

As I understand it, it assumes pretty much perfect headshot placement. 1) Gray squirrel/Fox Squirrel - 4.5fpe. 2) Eastern Cottontail/Swamp Rabbit - 4fpe. 3) Jack Rabbit White, Black, and Jack O' lope - 4.5fpe. 4) Raccoon/ Bandit - 9fpe.. if it's a big one, 10fpe. 5) Virginia Opossum/ County Rat - 10fpe.This is the best guide line to use. It is based on the Taylor knock out values and has been the standard energy to recomend for good clean one shot kills. This does not mean that less will not do only that 1000 ft/lbs for deer size game and 1500 ft/lbs for Elk size game works most of the time if the shot is well placed. 2500 ft/lbs is recommended for …Compound Bow: On the other hand, compound bows are capable of producing velocity of up to 270-310 FPS with 60- 100 Foot-Pound of kinetic energy for a successful and ethical kill. However, the Power stroke of Compound Bow is much better than a Crossbow.Location. Massachusetts. Had to go do the math, because I have zero idea what .534 slugs equates to... 440 Grain arrow at approximately 270fps is one example. Would be better if you can post your arrow speed / weight because most people are going to be in the same position I was. I would not use killzones under any scenario for Elk.Energy gives us an idea of how much power there is to initiate things like bullet expansion and penetration, but does not guarantee that they will occur. It is generally recommended that a small bore (.24-.32 caliber) rifle bullet suitable for medium size (CXP2 class) game be carrying about 800 ft. lbs. of kinetic energy when it hits.WARNING: many published gunwriters have clearly explained why anything less that 1,000 ft-lbs of kinetic energy won't kill a whitetail deer. That I why I wisely selected a bison (american buffalo) to try a load generating sub-part ballistic performance on, rather than risk wounding a tough 90 lb. whitetail.KE = (arrow weight / 450240) x (velocity x velocity) Usually the advertised fps rating is achieved using the lightest arrow recommended for the bow. For example, a bow that uses a minimum arrow weight of 350 grains achieving 305 fps would have. (350/450240) x (305x305) = 72.3 ft/lbs of kinetic energy.

Kinetic energy is a property of a moving object or particle and depends not only on its motion but also on its mass. The kind of motion may be translation (or motion along a path from one place to another), rotation about an axis, vibration, or any combination of motions. Translational kinetic energy of a body is equal to one-half the product ...

Question: 3. When you apply the brakes of your car, the brake pads rub together and the frictional forces do negative work and remove the car's kinetic energy, but heat up in the process. Suppose we have a car where the brake pads have a combined mass of 8.0kg and are made of a material with a specific heat capacity of 840J/kg*c.

The Kill Vehicle may be going more than 7,000 miles per hour when it hits the hostile reentry vehicle. The target reentry vehicle (warhead) is also traveling about 15,000 miles per hour. The ...The unofficial rule regarding minimum KE to push an arrow through a deer is about 40 foot-pounds. Lower-poundage bows are slower than higher-poundage models. So, let’s say the bow is pushing a 350-grain arrow at 265 feet per second. That setup is delivering roughly 54 foot-pounds of KE and .411 slugs of momentum.On average, more than 6 million deer are killed by hunters in the United States per year, while approximately 10 million Americans hunt deer each year. In addition, more than 1.5 m...I remember reading 800 ftlbs for deer sized animals, but I think that is irrelevant. ... I figure as long as my bullet can penetrate the chest it will kill it. I used to read about 1200lbs energy being a minimum for guys who think about it. I would say your creedmor should kill antelope as far away as a guy can make a hit! Oct 6, 2020We need to figure out the kinetic energy (KE) of the arrow. So assuming we have a bow rated 320 FPS IBO speed, an if you have a 60 lbs. version of the bow set to 28″ draw length, with some accessories on the string, a 425 grain arrow would deliver approximately 59 ft-lbs of kinetic energy at point-blank range .If the car brakes over a distance of 50 m before coming to rest, what is the force of friction. Here's the best way to solve it. (a) (b) The energy gets dissipat …. Pkg 0.21 7. A car of 1200 kg is travelling at 20 m/s when it slams on the brakes. a.For instance, Hornady's popular 250-grain 20-gauge SST sabot slug produces 1,200 foot/pounds of energy at 100 yards, 983 foot-pounds (ft.-lbs.) at 150 yards, but then tails off to 815 ft-lbs at 200. Many state DNRs recommend 1,000 ft.-lbs. of energy at the target to anchor a deer, but there's no data that has shown that to be the benchmark. Michelle's Hoyt Trykon Sport, the one she used to kill the hog, is set at 40 pounds and has a draw length of just 23 inches. It launches a 320-grain carbon arrow/broadhead at 198 fps and produces about 28 pounds of kinetic energy. That's pretty light, but it's obviously enough to bring down a big hog and a whitetail.

I have seen recommendations of 45# for deer and 55# for elk if using fixed blade broadheads. If using mechanicals 55# for deer and 65# for elk. I think both of these are on the high side. I have a female customer killing deer consistently with 33# of KE and using Rage KE's. PASSTHRU ARCHERY - 828-273-2815.My (very general) rule of thumb, is that I like a 15-20 fpe gun for squirrel and cottontail, crows and smaller game, a 30-40 fpe gun for turkey, fox, raccoons, a 100-150 fpe gun for small antelope, coyote, bobcat, and a 200 - 400 fpe gun for deer, hogs, warthog, larger antelope, etc. But depending on the situation; such as the need to limit ...Let’s say you’re shooting a heavier arrow that weighs 500 gr. That means it has about 64 ft-lbs of kinetic energy when it leaves the bow. During the flight, some of that energy will be lost to wind resistance. When the arrow makes the impact with the deer, all of the remaining energy is transferred to the razor sharp edges of the broadhead.Instagram:https://instagram. craigslist bozeman mt carsciti aba number2101 140th st fort dodge iakendra young joc Accuracy trumps kinetic energy and momentum of the arrow. You could kill any whitetail deer with a 45 lb bow shooting a 300 grain arrow with a field point. But if you don't hit the vitals it wouldn't help shooting a 500 grain arrow with a 80 lb bow and a 3" head. You might end up with a dead deer but good luck finding him. chevy sonic overheating recallcodes in simple basketball The only condition is that you make an accurate shot. Depending on the speed of a 400-grain arrow traveling 170 feet per second, a single shot from a 400-grain arrow could kill a mature deer. It is generally accepted that an arrow needs a minimum KE of 40-foot pounds to pass through a deer. Generally, lighter bows are indeed slower than those ... Energy gives us an idea of how much power there is to initiate things like bullet expansion and penetration, but does not guarantee that they will occur. It is generally recommended that a small bore (.24-.32 caliber) rifle bullet suitable for medium size (CXP2 class) game be carrying about 800 ft. lbs. of kinetic energy when it hits. cvs broadway chicago il A 12-kg sled is moving at a speed of 3.0 m/s. At which of the following speeds will the sled have twice as much kinetic energy? 4.2. Why is the gravitational potential energy of an object 1 meter above the moon's surface less than its potential energy 1 meter above Earth's surface? The moon's acceleration due to gravity is less.Kintetic Energy Formula. The formula for K.E. as measured in ft./ lbs. is: Mass x Velocity-squared divided by 450,240, with Mass the total arrow weight and velocity is the arrow speed. So let’s say you have an arrow that weighs 400 grains that flies at a speed of 290 feet per second. Your equation would look like this: 290 x 290 x 400 / ...